7-4[3(c+2)-4c]=

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Solution for 7-4[3(c+2)-4c]= equation:


Simplifying
7 + -4[3(c + 2) + -4c] = 0

Reorder the terms:
7 + -4[3(2 + c) + -4c] = 0
7 + -4[(2 * 3 + c * 3) + -4c] = 0
7 + -4[(6 + 3c) + -4c] = 0

Combine like terms: 3c + -4c = -1c
7 + -4[6 + -1c] = 0
7 + [6 * -4 + -1c * -4] = 0
7 + [-24 + 4c] = 0

Combine like terms: 7 + -24 = -17
-17 + 4c = 0

Solving
-17 + 4c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '17' to each side of the equation.
-17 + 17 + 4c = 0 + 17

Combine like terms: -17 + 17 = 0
0 + 4c = 0 + 17
4c = 0 + 17

Combine like terms: 0 + 17 = 17
4c = 17

Divide each side by '4'.
c = 4.25

Simplifying
c = 4.25

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